0=2.5x^2-x-40

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Solution for 0=2.5x^2-x-40 equation: 



0=2.5x^2-x-40

We move all terms to the left:

0-(2.5x^2-x-40)=0

We add all the numbers together, and all the variables

-(2.5x^2-x-40)=0

We get rid of parentheses

-2.5x^2+x+40=0

a = -2.5; b = 1; c = +40;
Δ = b2-4ac
Δ = 12-4·(-2.5)·40
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{401}}{2*-2.5}=\frac{-1-\sqrt{401}}{-5}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{401}}{2*-2.5}=\frac{-1+\sqrt{401}}{-5}
$

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